(3u+6)(u^2+2u-3)=0

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Solution for (3u+6)(u^2+2u-3)=0 equation:


Simplifying
(3u + 6)(u2 + 2u + -3) = 0

Reorder the terms:
(6 + 3u)(u2 + 2u + -3) = 0

Reorder the terms:
(6 + 3u)(-3 + 2u + u2) = 0

Multiply (6 + 3u) * (-3 + 2u + u2)
(6(-3 + 2u + u2) + 3u * (-3 + 2u + u2)) = 0
((-3 * 6 + 2u * 6 + u2 * 6) + 3u * (-3 + 2u + u2)) = 0
((-18 + 12u + 6u2) + 3u * (-3 + 2u + u2)) = 0
(-18 + 12u + 6u2 + (-3 * 3u + 2u * 3u + u2 * 3u)) = 0
(-18 + 12u + 6u2 + (-9u + 6u2 + 3u3)) = 0

Reorder the terms:
(-18 + 12u + -9u + 6u2 + 6u2 + 3u3) = 0

Combine like terms: 12u + -9u = 3u
(-18 + 3u + 6u2 + 6u2 + 3u3) = 0

Combine like terms: 6u2 + 6u2 = 12u2
(-18 + 3u + 12u2 + 3u3) = 0

Solving
-18 + 3u + 12u2 + 3u3 = 0

Solving for variable 'u'.

Factor out the Greatest Common Factor (GCF), '3'.
3(-6 + u + 4u2 + u3) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-6 + u + 4u2 + u3)' equal to zero and attempt to solve: Simplifying -6 + u + 4u2 + u3 = 0 Solving -6 + u + 4u2 + u3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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